Back to chapter

7.5:

Atomic Nuclei: Nuclear Spin State Population Distribution

JoVE 핵심
Analytical Chemistry
JoVE 비디오를 활용하시려면 도서관을 통한 기관 구독이 필요합니다.  전체 비디오를 보시려면 로그인하거나 무료 트라이얼을 시작하세요.
JoVE 핵심 Analytical Chemistry
Atomic Nuclei: Nuclear Spin State Population Distribution

Languages

소셜에 공유하기

Near absolute zero temperatures, in the presence of a magnetic field, most nuclei prefer the lower energy spin +½ state to the higher energy spin −½ state.

At room temperature, the energy from thermal collisions distributes the spins more equally between the two states, as described by the Boltzmann distribution equation. 

N+ and N represent the number of spins predicted in the spin +½ and spin −½ states, respectively.

The energy difference between the spin states, ΔE, is expressed as hν, where h is the Planck constant and ν is the operating frequency of the NMR instrument. k is the Boltzmann constant, and T is the absolute temperature measured in kelvin.

For example, in a 60 MHz instrument, at 298 kelvin, the lower energy state has an excess population of approximately nine to ten among two million nuclei, which produce the NMR signal.

Using a higher operating frequency increases the energy gap and the excess population.

7.5:

Atomic Nuclei: Nuclear Spin State Population Distribution

Near absolute zero temperatures, in the presence of a magnetic field, the majority of nuclei prefer the lower energy spin-up state to the higher energy spin-down state. As temperatures increase, the energy from thermal collisions distributes the spins more equally between the two states. The Boltzmann distribution equation gives the ratio of the number of spins predicted in the spin −½ (N) and spin +½ (N+) states.

Figure1

Here, ΔE is the energy difference between the states, k is the Boltzmann constant (1.38 × 10−23 J·K−1), and T is the absolute temperature measured in kelvins. The energy difference can be expressed as hν, where h is Planck’s constant (6.626 × 10−34 J·s) and ν is the operating frequency of the NMR instrument.

Figure2

For example, in an instrument operating at 60 MHz at 298 K, the ratio is slightly less than 1 (0.999991), implying that the lower energy state has approximately 9 to 10 excess nuclei in a total population of about 2,000,000 nuclei. The excess population is small but significant, as these spins are responsible for the net magnetization that produces the NMR signal. Using a higher operating frequency increases the energy gap between the spin states and the excess population.