Consider a complex capacitor network with three groups of capacitors connected in parallel, and these groups are then connected in series with each other. Determine the equivalent capacitance between the terminals of this intricate circuit. To solve this, the group at the bottom of the circuit, consisting of four capacitors connected in parallel, is analyzed first. The sum of their capacitance gives an equivalent capacitance, represented by a single capacitor C3. Next, the middle group, having three capacitors in parallel, is considered. Again, adding up their capacitances gives the equivalent capacitance C2. Finally, consider the top group, which has two capacitors in parallel. The equivalent capacitance is calculated and represented with one capacitor, C1. Now, the complex circuit has been simplified into three capacitors connected in series. To determine the equivalent capacitance for this series combination, the sum of the reciprocals of each capacitance is taken, resulting in the inverse of the equivalent capacitance. Upon rearranging the terms, the equivalent capacitance of the entire circuit between the terminals is obtained.