6.14:
Frames: Problem Solving II
Consider a hydraulic hoist supporting a load.
Assuming a simplified schematic representation of this frame structure, what force is acting on BD and BF members, provided the member dimensions and the weight of the load are known?
Here, BF and BD are two force members, while EFG and EDC are multi-force members.
A free-body diagram for the member EFG indicating all the forces is drawn.
The vertical and horizontal components of the force FBF can be expressed using a slope triangle.
The moment equilibrium condition at joint E gives the force F BF .
Then, applying the horizontal force equilibrium condition at joint E, the horizontal reaction force at E is evaluated.
Similarly, the vertical force equilibrium condition gives the vertical reaction force at joint E.
Now, drawing a free-body diagram for the member EDC, the components of the force along BD can be expressed using another slope triangle.
Applying the moment equilibrium condition at point C, the force F BD is calculated.
6.14:
Frames: Problem Solving II
Consider a hydraulic hoist supporting a load of 1 kN. Assuming a simplified schematic representation of this frame structure, the force acting on BD and BF members can be determined.
The member dimensions and the weight of the load are known parameters. This structure can be considered a frame with BF and BD acting as two-force members, while EFG and EDC are multi-force members.
A free-body diagram for the member EFG is considered. The inclined force FBF can be resolved into the vertical and horizontal components. The moment equilibrium condition is applied to joint E.
The force FBF is calculated to be 1.546 kN. Then, the horizontal force equilibrium condition is applied at joint E.
Substituting the value of the horizontal component of FBF into the equilibrium equation, the horizontal reaction force at E is calculated as 0.375 kN. Similarly, the vertical force equilibrium condition is applied.
The calculated vertical reaction force at joint E is 0.500 kN.
Now, a free-body diagram for the member EDC is considered. The horizontal and vertical components of FBD can be expressed using a slope triangle. The moment equilibrium condition at point C is applied.
The force FBD is calculated as 1.677 kN.
Önerilen Okuma
- Hibbeler, R.C. (2016). Engineering Mechanics ‒ Statics and Dynamics. Hoboken, New Jersey: Pearson Prentice Hall. Pp 305.
- Beer, F.P.; Johnston, E.R.; Mazurek, D.F; Cromwell, P.J. and Self, B.P. (2019). Vector Mechanics for Engineers ‒ Statics and Dynamics. New York: McGraw-Hill. pp 330
- Meriam, J.L., Kraige, L.G., and Bolton, J.N. (2020). Engineering Mechanics ‒ Statics. Hoboken, New Jersey: John Wiley. pp 200