Consider a baggage tractor pulling a baggage cart with a force of 10,000 N at an angle of 30 degrees. If the cart offers a friction of 2,000 N while being towed, what is the work done on the cart to displace it by 10 m in a straight line? A free-body diagram is drawn to get a clear understanding of the forces. The forces perpendicular to the motion of the cart do not cause displacement of the cart, so no work is done by those forces. The forces in the x-direction are the component of the pulling force and the frictional force, which are summed vectorially. The total work done is the resultant force along the displacement times the displacement. Alternatively, the work done by each force can be first calculated and then summed. The work done by the perpendicular forces is zero. The pulling force and the frictional force are not perpendicular to the displacement and so contribute to the total work.