A 13 cm thick wall with a 100 m2 area and 1.5 W/mK thermal conductivity separates a room from the outer atmosphere, which is at 3 degrees Celsius. The outside surface of the wall is at 10 degrees Celsius, and its emissivity is 0.8. If the convective heat transfer coefficient is 15 W/m2K , find the total heat loss rate to the surrounding. Also, calculate the temperature of the inner surface of the wall. Here, all three mechanisms of heat transfer are involved. Heat is transferred from the inner to the outer surface of the wall through conduction, while heat loss to the surroundings occurs due to convection and radiation. The rate of heat loss through convection depends on the temperature gradient, surface area, and heat transfer coefficient. So, total heat loss to the surrounding due to convection and radiation can be calculated as 13.27 x 103 W. Employing the conservation of energy and substituting the terms in the heat equation, the temperature of the inner surface of the wall can be calculated.