Recall that an SN2 reaction follows a concerted mechanism, where the nucleophilic attack and the departure of the leaving group occur simultaneously. High electron density around the leaving group blocks the frontside of the substrate, which forces the nucleophile to initiate a backside attack. As the HOMO of the nucleophile effectively overlaps with the LUMO of the electrophile, a new bond begins to form, and simultaneously, the bond between the electrophile and the leaving group weakens. Concurrently, the angle between the substituents and the leaving group reduces from 109.5° to 90°, and the geometry of the carbon atom changes from tetrahedral — in the substrate — to trigonal bipyramidal, in the pentacoordinate transition state. However, to retain the tetravalency of carbon, the leaving group departs the transition state, and the geometry of carbon becomes tetrahedral once again. In the product, the substituents on carbon have turned inside out, resulting in an inverted tetrahedron — similar to an umbrella that flips in strong wind. Also, the nucleophile is placed directly opposite to the original position of the leaving group. In an achiral substrate, due to the plane of symmetry, the configuration of the inverted product is identical to that of the reactant, and therefore, no evident inversion is observed. On the contrary, a chiral substrate like (R)-2-bromobutane— with an asymmetric alpha-carbon — undergoes an apparent inversion in configuration, also known as Walden inversion, to give (S)-2-butanol with a reversed carbon stereocenter. Likewise, (S)-2-chloropentane undergoes an SN2 reaction to form (R)-2-pentanol. In a cyclic molecule, a trans substrate gives a cis product, while a cis substrate generates a trans product. Thus, SN2 reactions are stereospecific as the product's stereochemical outcome depends on the configuration of the substrate.